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Home » Programming » C Programming » Programs » Others » C program to check whether the given number is armstrong or not
Suryateja Pericherla Categories: Others. No Comments on C program to check whether the given number is armstrong or not
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In this article we will learn to implement a C program to check whether the given number is Armstrong or not. A C program is provided below that reads a number and prints whether it is a Armstrong number or not.

 

//C program to check whether the given number is an Armstrong number or not
#include<stdio.h>
#include<conio.h>
void main()
{
	int num,dup,sum;
	printf("Enter a +ve integer: ");
	scanf("%d",&num);
	dup=num;
	sum=0;
	while(num>0)
	{
		sum += (num%10)*(num%10)*(num%10);
		num/=10;
	}
	if(dup==sum)
		printf("Given number is Armstrong number");
	else
		printf("Given number is not an Armstrong number");
	getch();
}

 

Input and output for the above program is as follows:

Enter a +ve integer: 371
Given number is Armstrong number

 

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