Sorting an array in Java

In this article we will learn to implement sorting an array in Java. A Java program is provided below to read a list of numbers and sort them.

I have used exchange sort to sort the array in ascending order.

The program is as follows:

import java.util.*;
class Driver
{
	static void printArray(int arr[], int n)
	{
		System.out.println("Array elements are: ");
		for(int i : arr)
			System.out.print(i + " ");
		System.out.print("\n");
	}
	static int[] sort(int arr[], int n)
	{
		//Exchange sort to sort in ascending order
		for(int i = 0; i < n - 1; i++)
		{
			for(int j = i + 1; j < n; j++)
			{
				if(arr[i] > arr[j])
				{
					int temp = arr[i];
					arr[i] = arr[j];
					arr[j] = temp;
				}
			}
		}
		return arr;
	}
	public static void main(String[] args)
	{
		Scanner input = new Scanner(System.in);
		System.out.println("Enter no. of elements: ");
		int n = input.nextInt();
		int[] a = new int[n];
		for(int i = 0; i < n; i++)
		{
			a[i] = input.nextInt();
		}
		System.out.println("After sorting: ");
		printArray(sort(a, n), n);
	}
}

Input and Output of the above program is given below:

Enter no. of elements:
6
5 3 -1 0 7 2
After sorting:
Array elements are:
-1 0 2 3 5 7

If you need further explanation for this program, please comment below.

Suryateja Pericherla

Suryateja Pericherla, at present is a Research Scholar (full-time Ph.D.) in the Dept. of Computer Science & Systems Engineering at Andhra University, Visakhapatnam. Previously worked as an Associate Professor in the Dept. of CSE at Vishnu Institute of Technology, India.

He has 11+ years of teaching experience and is an individual researcher whose research interests are Cloud Computing, Internet of Things, Computer Security, Network Security and Blockchain.

He is a member of professional societies like IEEE, ACM, CSI and ISCA. He published several research papers which are indexed by SCIE, WoS, Scopus, Springer and others.