C program to multiply consecutive numbers in an array

In this article we will try to implement a C program to multiply consecutive numbers in an array. A C program is provided below to find the product of consecutive numbers in a given array.

For example if the given array is: 1 2 5 4 1 2, then the output should be 1*2*1*2, which is 4.

The program is as follows:

#include <stdio.h>
#include <conio.h>

int main() 
{
	int n;
	printf("Enter n: ");
	scanf("%d", &n);
	int a[20];
	printf("Enter array elements: ");
	for(int i = 0; i < n; i++)
		scanf("%d", &a[i]);
	int prod = 1;
	for(int i = 0; i < n - 1; i++)
	{
		if(a[i+1] - a[i] == 1)
		{
			prod *= a[i];
			//For last consecutive number in the array
			if(i+1 == n - 1)
			{
				prod *= a[i+1];
			}
			
		}
		else
		{
			if(a[i] - a[i-1] == 1 && i != 0)
			{
				prod *= a[i];
			}
		}
	}
	printf("Product of all consecutive numbers is: %d", prod);
	getch();
    return 0;
}

Input and output for the above program is as follows:

Enter n: 6
Enter array elements: 1 2 5 4 1 2
Product of all consecutive numbers is: 4

Suryateja Pericherla

Suryateja Pericherla, at present is a Research Scholar (full-time Ph.D.) in the Dept. of Computer Science & Systems Engineering at Andhra University, Visakhapatnam. Previously worked as an Associate Professor in the Dept. of CSE at Vishnu Institute of Technology, India.

He has 11+ years of teaching experience and is an individual researcher whose research interests are Cloud Computing, Internet of Things, Computer Security, Network Security and Blockchain.

He is a member of professional societies like IEEE, ACM, CSI and ISCA. He published several research papers which are indexed by SCIE, WoS, Scopus, Springer and others.